Wednesday, May 28, 2014

SS #4: Divine

Difficulty- 4/5

X= 12 As + 11 Bs + 8 Cs + 2 Ds

Identify X.

(A, B, C and D are all single words. Identify A, B, C and D from the image cryptically and connect them using the above equation to get X.)


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6 comments:

  1. UnknownMay 28, 2014 at 5:46 PM

    A- adtiya
    b- rudra
    c- vasu
    d- ashwin
    x- tridasha or 33 gods of indian pantheon
    in mahabharat there were 33 gods(devas)
    X=12a+11b+8c+2d

    ReplyDelete
  2. Shobhit NarainMay 28, 2014 at 5:48 PM

    Thirty three Gods or Tridasha (The Pantheon of Vedic Demigods)
    12 Adityas + 11 Rudras + 8 Vasus + 2 Asvins

    ReplyDelete
  3. UnknownMay 28, 2014 at 6:09 PM

    X = Devtas
    A = Adityas (12)
    B = Rudras (11 forms of god Rudra)
    C = Vasus (8)
    D = Ashwins (Twins/2)

    ReplyDelete
  4. Queen of RandomMay 28, 2014 at 7:55 PM

    A - Aditya
    B - Rudra
    C - Vasu
    D - Ashvin

    In Ramayana, the 33 children of sage Kashyapa.

    ReplyDelete
  5. Apoorv KMay 28, 2014 at 8:19 PM

    X = 33 Gods
    A = Aditya (AB Group)
    B = Rudra (from HAL Rudra)
    C = Vasu (the movie)
    D = Ashwin (the cricketer)

    ReplyDelete
  6. ConquistadorMay 30, 2014 at 7:35 AM

    The correct answer is-
    A- Aditya
    B- Rudra
    C- Vasu
    D- Ashwin
    X- Together, they make up the Tridasha or the 33 Gods mentioned in the Rig Veda
    Points will be given only for a correct X.

    ReplyDelete

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